Write the equation of the line that is parallel to the line y = 2x + 2 and passes through the point (5, 3).
parallel lines have same slope so the slope is m=2 use the formula y-y1=m(x-x1) y-3=2(x-5) y-3 = 2x -10 2x-y=7
so the slope is 2 because its next to the x right? y=mx +b?
yes you are right =)
yes thanks :) & how would i do one if they asked me to show them a perpendicular one for example my next problem is this: Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).
the product of slopes of two perpendicular lines is (-1)
in this question the slope of the line would be -1/2
so its y = mx + b, what would be b for perpendicular lines?
like would b be 3 or 6?
use the formula y-y1=m(x-x1) where x1 and y1 are the coordinates of a point on the line here x1=6 and y1=3
i dont know how to use that formula :/
y-3=-1/2(x-6)
now just simplify
now what do i do with that? i got y = 2 & 2x -12
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3). a)y = 2x + 6 b)y = - x + 3 c)y = - x + 6 d)y = 2x + 3
thats the problem but i know its either a or b i just dont know which
in option (c) is it -x or -(1/2)x
i copied it wrong my bad
in option b its -1/2x +3
& option c its -1/2x +6
so if you simplify y-3=-1/2(x-6) you will get y= -1/2x +6 so it is c
thankssss so much ! are you busy right now ?
yw no im not...
you have fb i can msg better on ? i have like a couple more doubts :) ? lol
yes i have whats your name?? mine is ahmad hoblos =)
if i found the one whos actually you i sent you a request right now :)
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