Question

hey can anyone help me find the y and x intercepts for f(x)=x^2+3x+40

Answer 1

the x intercept is where f(x) equals zero so
0=x^2+3x+40
if you use the x= -b+/- \[\sqrt{b^2 - 4ac} and divide all that by 2a you get your answer.
for y intercept is where x equals zero so
f(x) = (0)^2 +3(0)+ 40
so f(x) = 0 + 0+ 40
f(x) = 40

Answer 2

I dont understand what you just wrote.....the question ask y=__________x=___________

Answer 3

Type an ordered pair

Answer 4

i don't want to give you the answer, it won't help you learn.
do you follow this?
f(x) can be considered as y.
so if x=0 for your y-intercept. then you will get y = 0^2+ 3(0) + 40
which ends up giving you y= 40

Answer 5

for x-intercept, y must equal 0
using quadratic formula you get...
x= -3 \[\pm\] \[\sqrt{3^2 -4(1)(40)}\] and then divide all of it by 2

Answer 6

are you sure thats your equation, not -40 ?