Question

Multiply.
(5x)(3x)(6x^2 – 1)
Answer

48x^3 – 8x

48x^4 – 8x^2

90x^3 – 15x

90x^4 – 15x^2

Answer 1

90x^4 – 15x^2

Answer 2

start with 5x and 3x it gives 15x^2

now multiply each term inside the brackets by 15x^2

Answer 3

do the same as instructed before

multiply together the outer terms and then distribute each into parenthess.

Answer 4

Yes as stated above:
Use the following order for such equations:


BODMAS

B Rackets first
O OF ( if there is of)
D Division ( if there is division)
M Multiplication ( if multiplication exists)
A Additition ( if there is addition)
S Subtraction ( if there is subtraction)

.example:

(5x)(3x)(6x^2 – 1)
1. work the brackets first

5x * 3x = 15x^2

2. Multiply the above into the left brackets:
15x^2 ( 6x^2 -1)
= 15x^2*6x^2 - 15x^2*1
= 90x^4 - 15x^2\[90x ^{4} - 15x ^{2}\]