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OpenStudy (anonymous):
Solve for x. x^2+14x+4=0 I tried the quadratic formula and got super confused!
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OpenStudy (mertsj):
a=1, b=14, c=4
OpenStudy (mertsj):
\[x=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]
OpenStudy (anonymous):
I am trying it again...give me one sec.
OpenStudy (anonymous):
computer randomly shut off...sorry.
OpenStudy (mertsj):
\[x=\frac{-14\pm \sqrt{196-4(1)(4)}}{2}=\frac{-14\pm \sqrt{180}}{2}=\frac{-14\pm6\sqrt{5}}{2}\]
\[x=-7\pm3\sqrt{5}\]
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OpenStudy (anonymous):
Ok so far I have this \[-14\pm \sqrt{18}/2\]
OpenStudy (mertsj):
How did you get 18?
OpenStudy (anonymous):
196-4(1)(4)...I am telling you I don't get this stuff.
OpenStudy (mertsj):
What is 4(1)(4)
OpenStudy (anonymous):
sorry meant 16
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OpenStudy (mertsj):
4(1)(4) is 16 and 196-16=180 NOT 18
OpenStudy (anonymous):
haha thats my bad...i just forgot to write down the zero on paper. LOL I feel stupid now.
OpenStudy (mertsj):
So now you understand?
OpenStudy (anonymous):
I think so...is that the answer then? Do I do any more steps?
OpenStudy (anonymous):
divide everything by 2
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OpenStudy (mertsj):
Did you see what I posted? Those are the steps and the correct answers are shown.
OpenStudy (anonymous):
Ok well thanks for working with me and helping me understand it more...
OpenStudy (mertsj):
yw
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