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Mathematics 24 Online
OpenStudy (anonymous):

the motion of an object is given by the displacement function s(t)=2t^3-7t^2+4t+1 where time is measured in second and distance is measured in meters a) use calculus to find the velocity and acceleration as a function of time b)find the velocity and acceleration when t=2seconds c)when is the object momentarily at rest?

OpenStudy (anonymous):

velocity is the first derivative acceleration is the second.

OpenStudy (anonymous):

got my velocity as zero and acceleration as 10

OpenStudy (anonymous):

but not sure

OpenStudy (anonymous):

v(t)=6t^2-14t+4

OpenStudy (anonymous):

a(t)=12t-14

OpenStudy (mertsj):

T\[s'=v=6t^2-14t+4\]

OpenStudy (mertsj):

\[s''=a=12t-14\]

OpenStudy (anonymous):

so the answer to the b)part is zero and 10?

OpenStudy (mertsj):

v(2)=0 a(2)=10

OpenStudy (mertsj):

yep

OpenStudy (anonymous):

the c)part

OpenStudy (anonymous):

??

OpenStudy (mertsj):

Would that not be when the velocity and acceleration are both 0?

OpenStudy (anonymous):

yeah it should be

OpenStudy (anonymous):

thanks alot

OpenStudy (mertsj):

yw

OpenStudy (mertsj):

I got .86 sec and 3.47 sec

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