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the motion of an object is given by the displacement function s(t)=2t^3-7t^2+4t+1 where time is measured in second and distance is measured in meters a) use calculus to find the velocity and acceleration as a function of time b)find the velocity and acceleration when t=2seconds c)when is the object momentarily at rest?
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velocity is the first derivative acceleration is the second.
got my velocity as zero and acceleration as 10
but not sure
v(t)=6t^2-14t+4
a(t)=12t-14
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T\[s'=v=6t^2-14t+4\]
\[s''=a=12t-14\]
so the answer to the b)part is zero and 10?
v(2)=0 a(2)=10
yep
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the c)part
??
Would that not be when the velocity and acceleration are both 0?
yeah it should be
thanks alot
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yw
I got .86 sec and 3.47 sec
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