Question

\[z=2^{-(x^2+y^2)}\] solve for y

Answer 1

take the base 2 log of both sides

\[\log _{2} = -(x^2 + y^2)\]

\[y^2 = -1(\log _{2}z + x^2)\]
then take the square root of both sides to find y

Answer 2

oops missing a z on the left hand side of my 1st statement

should be

\[\log _{2} z = -(x^2 + y^2)\]