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\[f(x,y) = 2^{x^2+y^2}\] draw level curves
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Usually I set k=f(x,y), solve for y, and then draw curves for different values of k What should I do in this case?
\[k=2^{-(x^2+y^2)}\\log_2k=-(x^2+y^2)\\-log_2k=x^2+y^2\] Looks like they are going to be circles, but with a negative radius?
x^2+y^2=ln(r^ln2)
r=1 x^2+y^2=1 circle
|dw:1331457001441:dw|
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r=2^ln2=2^0.69..=1.6168..
how did you get \[\ln(r^{\ln2})\]
|dw:1331457173657:dw|
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