f(x)=1/4 x^2

Question

f(x)=1/4 x^2

saifoo.khan · Answer

what's the question?

anonymous · Answer

If this is connected to your last question about if it had any roots, then yes, it does. In this context roots just mean when is this thing zero (aka intersects x-axis). So,

0 = (1/4)x²
Times 4.
0 = x²
Squareroot.
x = 0

Since we only got one answer, it only intersects the x-axis once.

anonymous · Answer

@saifoo.khan it says find the label the vertex and line of symmetry

saifoo.khan · Answer

vertex = (0,0)
line of sym, x = 0

anonymous · Answer

I agree with saifoo.khan's answer. If this graph had more than one x-intercept, then in order to find the vertex, you would average the x values. This is because a graph of degree 2 (biggest exponent is 2) is symmetrical so the x value of the vertex will always be right between the roots.

anonymous · Answer

Solve the formula for the given variable  A=3s^2, for s

saifoo.khan · Answer

$$\sqrt {\frac A 3}$$

anonymous · Answer

Give exact and approximate solutions to three decimal places (x-5)^2=4

saifoo.khan · Answer

3,7

anonymous · Answer

find the vertex and line of symmetry  f(x)=-x^2+10x+3