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find the vertex and line of symmetry. f(x)=3-x^2
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vertex is (0,3)
line of symmetry is x = 0
To find the vertex of a parabola, use the equation: y = a(x – h)^2 + k for an equation in the form of yours. in this case, h is zero for your equation. The vertex will always be the point (h,k)
k = 3
also, for your equation, f(0) = 3. Therefore, the point (0,3) represents the y-intercept of the graph
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line of symmetry comes from (x-h)...whatever x value will make x-h equal 0.
If you know your basic graph transformations well, you can easily see from the equation that this is just a parabola shifted up on the y axis by 3 units, but is inverted upside down due to the negative in front of x^2.
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