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y = x2^-x increases in which interval
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you mean \[y = x^{2} - x or y= 2x^{-x}\]
It'll be a parabolalke this http://www.wolframalpha.com/input/?i=y+%3D+x%5E2+-+x
if its is the first one, then for x<1/2
thanx wow u are a such true genius can u pls give me tips how to master my maths
ask siddhantsharan
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Hahaa... dude. A doubt here. y is minimum for x = 0.5 So it'll increase for both x > 0.5 And x < 0.5 ??
no, y', is negative for x >1/2
i mean x <1/2 , sry
DAmn. Forgot the differential. My bad. :D
so the function will increase in \[x \in(1/2,\infty )\]
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