Question

Can someone help me finish this? I'm a little stuck? lol :)

2x^2 + 27x + 13 = (x + 13)(2x + 1)

Step one: Identify a,b and c: a = 2, b = 27, c = 13
Step two: Multiply together a and c: (a)(c) = (2)(13) = 26
Step three: Since the sign of the middle term is positive, I need to find two positive factors of 26 with a sum of 27. Which are....

Answer 1

26 and 1

Answer 2

really you are going good with factors :)

Answer 3

Also, are these correct?

Factor completely: 2x2 + 9x + 4
(2x + 2)(x + 2)
(2x + 1)(x + 4)
(2x + 4)(x + 1)
(2x + 2)(x + 4)

I think (2x + 1)(x + 4) is right

2. Factor completely: 3x2 − x − 4
(3x – 1)(x + 4)
(3x + 4)(x – 1)
(3x – 2)(x + 2)
(3x – 4)(x + 1)

I think (3x – 4)(x + 1) is right

3. Factor completely: 10x2 + 2x − 8
2(5x – 1)(x + 4)
2(5x – 4)(x + 1)
2(5x + 2)(x – 2)
2(5x – 2)(x + 2)

I think 2(5x – 4)(x + 1) is right

4. Factor completely: 3x2 + 5x + 1
(3x + 1)(x + 1)
(3x + 5)(x + 1)
(3x – 5)(x + 1)
Prime

Im pretty sure this is a prime?

Answer 4

and Thanks, I've been studying hard for a big upcoming test :)

Answer 5

1.
(2x+1)(x+4)

Answer 6

and for step four of my first question, I have to write 27x as 26 + 1 and the factor by grouping right?

Answer 7

2x^2+9x+4
2x^2+8x+x+4
2x(x+4)+1(x+4)
(x+4)(2x+1)

Answer 8

yeah 27x=26x+x

Answer 9

Okay, thanks! what about the other ones I have up there?

Answer 10

2x^2 + 27x + 13 = 2x^2 + 26x + x + 13
= (2x^2 + 26x)+(x + 13)

what do I do next? idk why I get stuck on this part, lol :)

Answer 11

I know the answer is (x + 13)(2x + 1) but I'm missing a step in between there....

Answer 12

4. can not be factorized and yeah it is prime you can use quadratic formula or can work on it by the method of completing the square

Answer 13

2x^2+27x+13
2x^2+26x+x+13
2x(x+13)+1(x+13)
(x+13)(2x+1)

Answer 14

thanks so much, are all of the other correct as well?

Answer 15

10x2 + 2x − 8
2(5x – 1)(x + 4) yeah they all are correct :)

Answer 16

awesome, thanks so much! I really appreciate all of your help! :D

Answer 17

my pleasure and working with maths is my passion :)

Answer 18

:D