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Please help! Determine algebraically whether h(x)=x^3-x^2-x is odd, even, or neither.
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Neither. Note the mix of even and odd exponents.
An even function is where h(-a) = h(a). An odd function is where h(-a) = -h(a). Try substituting x= -x into the equation and seeing if they are equal.
Thanks guys! :)
The sum of an even function and an odd function is neither even nor odd. This function can be broken into \[h(x)=x^3-x^2-x =(x^3-x)-x^2\]
x^3-x is odd, x^2 is even.
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