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OpenStudy (anonymous):
What volume of 0.0962 M NaOH is required to exactly neutralize 10.00 ml of 0.128 M HCl?
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OpenStudy (callisto):
no. of mole of HCl = 0.01 x 0.128 = 1.28x10^3 no of mole of NaOH = no of mole of HCl =1.28x10^3 vol of NaOH required = 1.28x10^3/0.0962 x1000 = 13.3ml
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