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What is the m∠ADC? (I will attach picture)
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Isos triangle thm, angles D and A are congruent. Since ext angle = sum of two remote int angles, 115 = m<A +m< D Since they're the same, 115 = 2m<ADC m<ADC = 115/2
Thank you !!
@Luis Rivera, the angles opposite the congruent sides are A and D, not A and ACD. When you said m<ADC = 180 - 130 = 50, that relied on 130 being the measure on the other two angles. That number came from 65 * 2, but angles A and ACD are not congruent. A is congruent to D, not ACD.
On the picture you marked that A and D were congruent. If you say that m<ADC = 50, then m<A = 50 as well. Then by defn supplementary, the third angle is 65 degrees. 180° in a triangle, but 50 + 50 + 65 doesn't = 180. It = 165.
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