Question

a square garden plot

Answer 1

area of a square = s²
perimeter of a square = 4.s

area of the first garden:
\[s ^{2}=125\]
\[s= \sqrt{125}\]
\[s= 5.\sqrt{5}\]

perimeter of the first garden:
\[p= 4.s\]
\[p= 4.5\sqrt{5}\]
\[p= 20\sqrt{5}\]

area of the second garden:
\[s ^{2}=405\]
\[s= \sqrt{405}\]
\[s= 9\sqrt{5}\]

perimeter of the second garden:
\[p=4.s\]
\[p=4.9\sqrt{5}\]
\[p=36\sqrt{5}\]

now we have both perimeters, do we can just subtract one from the other:

\[36\sqrt{5}-20\sqrt{5}= 16\sqrt{5}\]

Answer 2

\[P _{1}-P _{2} = 4a _{1}- 4a _{2} = 4(a _{1}-a _{2})\]\[= 4( \sqrt{405}-\sqrt{125})= 4* 4\sqrt{5}= 16\sqrt{5} ft\]