Question

what is the di/dx of y = cot^-1 (tan2x)?
a. -2
b. 2
c. tan2x
d. -cot 2x

Answer 1

what is a di?

Answer 2

i think dy/dx

Answer 3

ops dy/dx sorry

Answer 4

:) i thought so to but can never be too sure

Answer 5

w8 i check the other question i think i put di/dx LOL i fix it

Answer 6

y = cot^-1 (tan2x) re write it as

cot(y) = tan(2x) and derive

Answer 7

-csc^2(y) y' = 2 sec^2(2x)

y' = -2 sec^2(2x)/csc^2(y)

Answer 8

iron out the y spot and simplify

Answer 9

i get -2 here

Answer 10

then with any luck, its -2 :)

Answer 11

thanks god bless

Answer 12

its best to iron out the y spot tho to be sure ... and if you have already done that then I trust your judgement

Answer 13

the wolf agrees ;)

Answer 14

i fix the question here sorry http://openstudy.com/study#/updates/4f5df87fe4b0602be438c4be sorry before