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Physics
OpenStudy (anonymous):

We measured the radius of the orbit and found it to be r = 1.95 m and we measured the period of the orbit as T = 2.2 seconds. What is the angle θ in the diagram below?

OpenStudy (anonymous):

OpenStudy (mani_jha):

Is the length L given?

OpenStudy (anonymous):

In order to find the angle you must first find the velocity and from that the acceleration. Since \[v= (2\pi r)\div T\] \[v=(2\pi 1.95)\div 2.2\] \[=5.57ms ^{-1}\] therefore \[\tan \theta=v ^{2} \div r.g =\tan^{-1} 95.57^{2} \div1.95 \times 9.8)\]\[\theta = 80.80\]

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