Question

We measured the radius of the orbit and found it to be r = 1.95 m and we measured the period of the orbit as T = 2.2 seconds.
What is the angle θ in the diagram below?

Answer 1

Is the length L given?

Answer 2

In order to find the angle you must first find the velocity and from that the acceleration.
Since \[v= (2\pi r)\div T\]
\[v=(2\pi 1.95)\div 2.2\]
\[=5.57ms ^{-1}\]
therefore \[\tan \theta=v ^{2} \div r.g =\tan^{-1} 95.57^{2} \div1.95 \times 9.8)\]\[\theta = 80.80\]