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OpenStudy (anonymous):
True or false for the integral:
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OpenStudy (anonymous):
OpenStudy (anonymous):
I think it's false, because there's a mistake on the right integral. The lower value is on the top.
OpenStudy (anonymous):
@ghass1978 what do you think it is?
OpenStudy (anonymous):
sorry i was away,its true
OpenStudy (anonymous):
looks true to me as well make the u- sub \[u=25-x^2, -\frac{1}{2}du=xdx, u(0)=25,u(3)=16\]
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OpenStudy (anonymous):
I came up with the same thing using u-sub, but why is the lower value on the top of the integral?
OpenStudy (anonymous):
because your sub is \[u=25-x^2\]
OpenStudy (anonymous):
so when you replace x by 0 you get 25 and when you replace x by 3 you get 16 just works out that way
OpenStudy (anonymous):
ohh...I figured that it wasn't allowed. Thanks!
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