OK, Express the equation in logarithm form (use the same variable): e^4x+40=200

WHICH I FOUND: LN(200)=4X+40

BUT how do i Solve the equation for x.
x =

Question

OK, Express the equation in logarithm form (use the same variable): e^4x+40=200 

WHICH I FOUND: LN(200)=4X+40

BUT how do i  Solve the equation for x.
x =

anonymous · Answer

should this look like e^(4x+40)=200 or e^(4x)+40=200 ?

anonymous · Answer

the answer? or the equation?

anonymous · Answer

the equation

anonymous · Answer

yes the first one

anonymous · Answer

then you just solve for x, ln(200) is not a "pretty" number so leave it as the ln its the exact answer instead of trying to round it

anonymous · Answer

ok but how can i write it out w/ ln(200) as is? i mean 4x+40 part

anonymous · Answer

because they want me to solve for x

anonymous · Answer

ln(200) is jsut a number like any other just solve forxlike you would ifit was n=4x+40

anonymous · Answer

so it would be x= ln(200)-40/4??

anonymous · Answer

yep

anonymous · Answer

oh ok

anonymous · Answer

thanx