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i^34
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Can you tell me what the remainder is when divide 34 by 4?
Always divide the exponent by 4 and see what the remainder is...
so then you will have \[i^R\] where R is the remainder @Luis Rivera We have a new code of conduct. I'm trying to get people to know about it. So one of the things it says is to not just post the answer.
i = sqrt(-1) i^2 = -1 i^3 = -i i^4 = i^2*i^2 = -1*-1 = 1 keep doing this and notice that every multiple of 4 the answer is 1 for example i^12=1, i^16=1, etc. closest number 34 that is a multiple of 4 is 32. so i^32=1 but i^34 = i^32*i^2 = 1*-1=-1
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\[i^{4(Q)+R}=(i^4)^Q i^R=(1)^Q i^R=1 \cdot i^R=i^R\]
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