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Physics 20 Online
OpenStudy (anonymous):

Can anyone help me with this? : http://i.imgur.com/aaBhz.jpg I have the free-body diagram drawn and I think I have to break up the components but I can't find the angles

OpenStudy (anonymous):

For part A) is it just T = ma = m(v^2/r)?

OpenStudy (mani_jha):

Yes. Same for the second part. For the third part apply the work-energy theorem(The work done is equal to the change in kinetic energy). Try it

OpenStudy (anonymous):

I don't get the third part. W = force * distance so it's ΔT * Δr?

OpenStudy (mani_jha):

No,As I said it is the change in kinetic energy: \[W=mv 1^{2}/2-mv2^{2}/2\] where v1 is the initial velocity and v2 is the final velocity. Now, can you do it?

OpenStudy (anonymous):

yeah I got it now thanks :)

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