Question

How do you solve 2sin^2 (theta) + cos(theta)=2?

Answer 1

try substituting (sin^x)^2=1-(cos^x)^2

Answer 2

60 OR 90 DEGREE

Answer 3

\[2\sin^2\theta+\cos \theta=2\]
We know that:
\[\sin^2\theta = (1-\cos^2\theta)\]
So we can substitute and get:
\[2(1-\cos^2\theta)+\cos \theta = 2\]