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Mathematics 10 Online
OpenStudy (anonymous):

What is the vertex of this equation? h = -16t^2 + 65t + 4

OpenStudy (anonymous):

can u give me the general equation that can help us how to find the vertex?

OpenStudy (anonymous):

I don't really know. I think that is all of the question.

OpenStudy (anonymous):

hmm let me look it up

OpenStudy (anonymous):

Okay. Thank you so much for trying to help me. :)

OpenStudy (anonymous):

\[y = a(x – h)^2 + k\] where (h;k) is the vertex

OpenStudy (anonymous):

Okay, so what is the vertex of this equation I posted?? :P

OpenStudy (anonymous):

im working on it lol relax..

OpenStudy (anonymous):

Okay. Sorry, I'm chill. xD

OpenStudy (anonymous):

\[h = -16t^2 + 65t + 4\]\[x=-b/(2a)\] is the x-coordinate of the vertex

OpenStudy (anonymous):

\[-65/(2*(-16))\]

OpenStudy (anonymous):

Okay, thank you Brutal! You so rock!

OpenStudy (anonymous):

\[65/32\] is the x coordinate or to find y coordinate just find h(65/32)

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