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What is the vertex of this equation? h = -16t^2 + 65t + 4
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can u give me the general equation that can help us how to find the vertex?
I don't really know. I think that is all of the question.
hmm let me look it up
Okay. Thank you so much for trying to help me. :)
\[y = a(x – h)^2 + k\] where (h;k) is the vertex
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Okay, so what is the vertex of this equation I posted?? :P
im working on it lol relax..
Okay. Sorry, I'm chill. xD
\[h = -16t^2 + 65t + 4\]\[x=-b/(2a)\] is the x-coordinate of the vertex
\[-65/(2*(-16))\]
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Okay, thank you Brutal! You so rock!
\[65/32\] is the x coordinate or to find y coordinate just find h(65/32)
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