Ask your own question, for FREE!
Mathematics 21 Online
OpenStudy (anonymous):

x>0lim5x-7sinx/3x

OpenStudy (anonymous):

\[\lim_{x \rightarrow 0}5x-7sinx/3x\]

OpenStudy (mertsj):

The limit of a sum is the sum of the limits

OpenStudy (anonymous):

/ mean division

OpenStudy (anonymous):

Mertsj! I'm From Iran

OpenStudy (anonymous):

I don't type English

OpenStudy (anonymous):

my english is very bad

OpenStudy (anonymous):

\[limsin3x -\sin5x \div3x\]

OpenStudy (mertsj):

\[\lim 5x-\frac{7\sin(x)}{3x}=5(limx)-\frac{7}{3}(\lim\frac{\sin(x)}{x})\]

OpenStudy (mertsj):

The limit of x as x approaches 0 is 0

OpenStudy (mertsj):

So we have \[\frac{-7}{3}(\lim\frac{\sin(x)}{x})\]

OpenStudy (mertsj):

\[\frac{-7}{3}\lim\frac{\sin (x)}{x}=\lim\frac{\frac{d \sin (x)}{dx}}{\frac{dx}{dx}}\]

OpenStudy (mertsj):

\[\frac{-7}{3}(\lim \cos (x))=\frac{-7}{3}\]

OpenStudy (mertsj):

So -7/3 is the desired limit.

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!