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x>0lim5x-7sinx/3x
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\[\lim_{x \rightarrow 0}5x-7sinx/3x\]
The limit of a sum is the sum of the limits
/ mean division
Mertsj! I'm From Iran
I don't type English
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my english is very bad
\[limsin3x -\sin5x \div3x\]
\[\lim 5x-\frac{7\sin(x)}{3x}=5(limx)-\frac{7}{3}(\lim\frac{\sin(x)}{x})\]
The limit of x as x approaches 0 is 0
So we have \[\frac{-7}{3}(\lim\frac{\sin(x)}{x})\]
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\[\frac{-7}{3}\lim\frac{\sin (x)}{x}=\lim\frac{\frac{d \sin (x)}{dx}}{\frac{dx}{dx}}\]
\[\frac{-7}{3}(\lim \cos (x))=\frac{-7}{3}\]
So -7/3 is the desired limit.
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