Question

Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3)

Answer 1

your slope for a perpendicular line is opposite reciprocal
a and -1/a
your slope is 2 the opposite reciprocal is -1/2
now use (6,3) to find your equation

Answer 2

umm and how do you do that?

Answer 3

Slope of given line is 2. So, slope of perpendicular line will be -1/2.

So, the new line is:
y = -x/2 + b. Find b using point given 6,3 for x and y. Then, you have your line.

Answer 4

how did yu get that

Answer 5

3 = -6/2 + b
3 = -3 + b
b = 6.

So, line is:
y = -x/2 + 6

Answer 6

Perpendicular lines have slopes that multiply to -1.

So, if slope m1 = 2 and its product with m2 = -1, you have 2 * m2 = -1 => m2 = -1/2

Answer 7

oK thanks