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find the value, sin(cos^-1(radical2/2)) im lost, just need a hint of how to go about this problem i.e. set it up
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cos^-1 means the inverse cosine, the angle x such that cos(x)= sqrt(2)/2 There are a few angles it is good to memorize their sin,cos, and tan in degrees: 0,30,45,60,90 where in order sin,cos,tan we get 0,1,0 1/2, sqrt(3)/2 , 1/sqrt(3) sqrt(2)/2, sqrt(2)/2, 1 sqrt(3)/2,1/2, sqrt(3) 1,0,undf
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