using the addition method,solve each system of equations using the addition method,solve each system of equations x+y=-3 x= 1
ok for this one all you need to go is plug 1 in for x so you will have 1+y=-3 now subtract the one to the other side and y=-4
got there now what
isn't this the substitution method???
yes now dont i have to find x
ohh wait we already got x its 1 lol
no your objective was to find y so y=-4 now you can plug it back into the equation and you get: 1+-4=-3 and that is true
i got the check done.. can you help me with a few more like these sorta
yes :)
k here it is 3x - 5y=8 5y=10
3x - 5y=8 5y=10
Ok so this is how we set the problem up 3x-5y=8 5y=10 now we add downwards, so the y cancels out because -5y+5y= 0 and then we have to add 8+10 which equals 18 so now we have 3x=18 divide 3 by both sides and you are left with x=6 now for the fun part :) since we know x now, we can simply plug it into the top part of the problem 3x-5y=8 plug in 6 for x and we have 3(6)-5y=8 that is really just 18-5y=8 now we subtract 18 from both sides and we have: -5y=-10 if we divide -5 by -10 we get 2 so y=2 plugging all this into the equation 3x-5y=8 3(6)-5(2)= 8 and this is true :)
thank you so much!.. can you help me with like two more questions like this
yah do you want me to explain everything again, or just show you the steps quickly? Do you understand how to do it?
2x+6y=5 2x-3y=-4
just show me the steps sorta like what u just did but with less words and if i need help ill post heere if i need help
okay!
2x+6y=5 2x-3y=-4 ok for this problem theres nothing we can make zero right away so we have to multiply by two to get the -3y to -6y so then we can subtract. make sure to multiply by 3 for EVERY variable 2x+6y=5 4x-6y=-8 6x=-3 x=-.5 now we can plug in the x in either equation it doesnt matter 2(-.5)+6y=5 -1+6y=5 6y=6 y=1 check: 4(-.5)-6(1)=8
sorry thats a -8***
thanks. i need help with a few more if your okay with helping
can you try them on your own and show me where you need help?
wait the equation is not correct cause when u go to check it doesnt fit back in and equal the correct answer
yes it does 4(-.5)=-2 6(1)=6 -2-6=-8
oh okay.. can you work through this one with me x+2y=9 3x-2y=7
can you please try it first on here and show me what you dont understand
4x=16 x=4 4+2y=9 2y=5 y=5/2
so u ad 3x +x and got 4x
yes!
but then you replace 4 from the x to make 4+2y=9
then what do u do with that 4
subtract it from 9 because you want the y's on one side
oohhh
Does this all make sense, do you have any questions?
i have one more problem like this but how would u do the check for this one
x+2y=9 (4)+2(5/2)=9
wait i got it :) i need help walkin me through one more like u just did
okay can i see you try it for me please!
yes and can u help me if i get stuck
of course, thats our job here at openstudy :)
x+3y=11 x+3y=7
u would add 3+3 right to make 6
x=8
no you cant do that you want to cancel a letter (variable) out so you need to multiply
grrr
so what would be the easiest to do
ugh these are the trickier ones, wait one second well I get my book
okay
this problem appears like it is a substitution one
no its an addition method one
x+3y=11 x+3y=7
do i have to solve that? I can only show the steps
use addition method
multiply the 2nd equation by -1 and add them
that would cancel everything out
Actually obviously there are no solutions there.. x+3y cannot equal to 11 and 7 at the same time.
it's inconsistent, or whatever u call it.
yah that is what i thought
thanks :)
Kk here we go: x+y=-3 x= 1 You can look at this as: x+y=-3 x+0y= 1 You can then add the negative: x + y = -3 + - (x + 0y = 1) Which is: x + y = -3 + -x = -1 ------------ 0 + y = -4
You already know what x =, because that's part of your two initial equations. Now you know that y = -4, as well, and you've solved the system.
Lol. Never mind, looks like the question evolved from that to something else...
im confused
no that will not work for x+3y=11
This problem is inconsistent therefore there is not an anwer that will solve both at the same time
think about it, its the same variables so they can only equal one number not two at the same time
okay so it cant be workable..
correct :)
thank you so much for your help..
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