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Calculus III: find the center of mass of a 3-4-6 triangle by use of a double integral
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first we need to come up with functions
alright. How do we go about that?
are you sure it is not 3-4-5 triangle ?
no, it's a 3-4-6
I emailed him and he said something about law of cosines, b/c it's not a right triangle
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*emailed teacher
alright, your professor sucks
agreed
alright, let's find one angle using law of cosines http://www.mathsisfun.com/algebra/trig-cosine-law.html 3^2=4^2+6^2-2(4)(6) cos(C) 9=16+36-48 cos(C) 43=48 cos(C) 43/48 = Cos(C) C=0.460493
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