Question

y+x^2=2x
y+2x=4 find the solutions

Answer 1

Solve the bottom one for 2x by subtracting y on both sides

Answer 2

Then you have both equations =2x

Answer 3

y=4-2x
put it into y+x^2=2x

(4-2x)+x^2=2x
x^2-2x+4=2x
x^2+4=0

Answer 4

So that means whatever they equal must equal

Answer 5

Or solve for y like cyclets did

Answer 6

thanks

Answer 7

And also one thing there is an error
-2x-2x=-4x

Answer 8

ops..sorry..

y=4-2x
put it into y+x^2=2x

(4-2x)+x^2=2x
x^2-2x+4=2x
x^2-4x+4=0
(x+2)(x-2)=0

Answer 9

(x-2)(x-2)=0

Answer 10

so would the points be 2,0 and -2,8

Answer 11

the point is 0,0 to 2,0

Answer 12

wouldnt the x's be 2 and -2 though

Answer 13

I think he meant (x-2)(x-2)=0
which will get you one zero with multiplicity 2
x=2
So to find what y is just plug in 2 for x and solve for y (just use one of the equations given)

Answer 14

yes..thanks myininaya ~ appreciate that