Question

how would you solve t^2 - 4t - 165 = 0 by completing the square?

Answer 1

\[t^2-4t+4=165+4\]
\[(t-2)^2=169\]

Answer 2

Now take the square root of both sides and don't forget there are 2 square roots of 169

Answer 3

t^2 - 4t - 165 = 0
(t^2 - 4t +4) -4-165 =0
(t-2)^2 -169 =0
(t-2)^2=169
(t-2) = 13 or (t-2) = -13
t = 15 or t = -11

Answer 4

thank you

Answer 5

yw