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Could someone help me answer this question? The area of a square varies directly with the square's side length. If the area of a square with side length of 6.4 in. is 40.96 in.2, what is the area of a square with a side length of 7.96 in.?
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This is a sample problem
easy.. \[A=ks^2\]
\[40.96=k*6.4^2\]\[k=40.96/(6.4^2)\]
\[A=\frac{40.96}{6.4^2}*7.96^2\] idk what that is, use a calculator
Thank God for calculators
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Aha! Thank youuu Bah! Hold on, let me give yo a medal
Is that right? The area of a square with a side length of 7.96 in is 63.3616^2.
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