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Is f(x) = √(x-3)^2+3 a function? How do I know it's a function and its domain and range?
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\[f(x)=\sqrt{(x-3)^2}+3\] is that the question? if so... it can be simplified..
\[\sqrt{x-3}^2+3\] \[\cancel{\sqrt{}}x-3\cancel{^2}+3\] \[x-3+3\] \[x\] y=x is a line.
\[\sqrt{f^2}=|f|\]
yes that is the question
\[|x-3|+3\]
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why is it an absolute value, how did you get it like that? o.o
if you square a real number it is always non-negative (zero or positive) when you take the principal value of the square root of a non-negative number you get a non-negative number
yup. What do you mean by the principal value of the square root?
the square root of 4 is \(\pm2\) the principal value of the square root of 4 is 2.
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