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OpenStudy (anonymous):
Find the length of the major axis of the ellipse with equation 9(x+4)^2+4(y-1)^2=36
A)4
B)18
C)6
D)9
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OpenStudy (amistre64):
the 9 and 4 give it away since we got a 36 over there; so the unders go to 9 and 4; since 9 is bigger sqrt it and double it
OpenStudy (anonymous):
so the answer is 9?
OpenStudy (amistre64):
no, the answer is based on the 9
OpenStudy (amistre64):
2sqrt(9)
OpenStudy (anonymous):
so its 4
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OpenStudy (amistre64):
maybe ....
OpenStudy (anonymous):
i think im gonna go with 4
OpenStudy (anonymous):
it may be 3
OpenStudy (amistre64):
i wouldnt go with 4 ...
OpenStudy (anonymous):
3 isnt an option lol
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OpenStudy (amistre64):
3 is closer than 4 ;)
OpenStudy (anonymous):
i dont understand lol
OpenStudy (amistre64):
2 sqrt(9) doesnt equal 4
OpenStudy (anonymous):
18
OpenStudy (amistre64):
you need new batteries in your calculator i think
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OpenStudy (anonymous):
18 isnt right either
OpenStudy (amistre64):
nope, it aint
so, it aint 9, it aint 4, and it aint 18
OpenStudy (anonymous):
\[\left( \frac{x+3}{2} \right)^2+\left( \frac{y-1}{3} \right)^2=1\]
OpenStudy (anonymous):
|dw:1331966516957:dw|
OpenStudy (anonymous):
\[\left( \frac{x+4}{2} \right)^2+\left( \frac{y-1}{3} \right)^2=1\]
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OpenStudy (anonymous):
it should be 3
OpenStudy (anonymous):
sorry 2*3=6 major
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