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Use Half-Angle Identity to evaluate:
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\[\sin 105^{\circ}. \] So far I have: \[\sin (\frac{210}{2}) = \pm \sqrt{\frac{1-\cos\theta}{2}} . \] What should I do now? How do I find out \[\cos\theta ? \] Please help!!
Any Ideas?
Would you draw a 210 degree triangle?
Which would be a 30-60-90
you want sin(105) so let theta = 210 so that sin(105) = sin(210/2)
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Here's where I'm stuck now:
you can do that too... according to the formula you need cos(210) right?
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