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Mathematics 11 Online
OpenStudy (anonymous):

Use Half-Angle Identity to evaluate:

OpenStudy (anonymous):

\[\sin 105^{\circ}. \] So far I have: \[\sin (\frac{210}{2}) = \pm \sqrt{\frac{1-\cos\theta}{2}} . \] What should I do now? How do I find out \[\cos\theta ? \] Please help!!

OpenStudy (anonymous):

Any Ideas?

OpenStudy (anonymous):

Would you draw a 210 degree triangle?

OpenStudy (anonymous):

Which would be a 30-60-90

OpenStudy (anonymous):

you want sin(105) so let theta = 210 so that sin(105) = sin(210/2)

OpenStudy (anonymous):

Here's where I'm stuck now:

OpenStudy (anonymous):

you can do that too... according to the formula you need cos(210) right?

OpenStudy (anonymous):

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