Lyle has a bowl of fruit on his dining room table. It contains 4 oranges, 3 apples, and 3 peaches. Suppose he selects a piece of fruit at random from the bowl. What is the probability that he selects either an orange or an apple?
Choices:
thirty percent
forty percent
ten percent
seventy percent
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OpenStudy (anonymous):
Soo i think since theres 10 pieces of fruit in all and i think "or" means add, so 4/10 plus 3/10 is 7/10 which is 70%???
OpenStudy (anonymous):
nevermind then...dont listen to me xP
OpenStudy (anonymous):
there is no 20%
OpenStudy (anonymous):
im probably wrong, go with his answer
OpenStudy (anonymous):
HA im good!! do my answer!!
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OpenStudy (anonymous):
20% is not a choice!!! lol adele..
OpenStudy (anonymous):
its 70%!!! right?
OpenStudy (anonymous):
i was so confident about this one man xP
OpenStudy (anonymous):
^ thats confusing, what?
OpenStudy (anonymous):
Okaayy, since theres 10 in all and "or" means add, then you would take 4/10 plus 3/10. Which gets 7/10 which is the simplified form of 70/100 which is 70%, right? Right?? :O
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