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Mathematics 19 Online
OpenStudy (anonymous):

help me creating a word problem

OpenStudy (anonymous):

the project i have to do is like this: http://mrskrummel.com/documents/tissueBoxProblem.pdf

OpenStudy (anonymous):

my idea was to do something like The velocity of a moving object can be described as v(t)=t^2v(t)=t2 where t is in seconds and v is meters per second.. If the object starts at v=0 when t=0, how far has it traveled after 30 seconds?

OpenStudy (anonymous):

how can i make that into a theme that i can decorate a tissue box about it?

OpenStudy (anonymous):

help please

OpenStudy (anonymous):

That's a good idea. You could make the theme speed and decorate it either with fast things, or as a fast thing itself... My first thought is to make a box into a drag-racer... Hopefully that helps in some way...

OpenStudy (anonymous):

that's a good idea, but how do you think i can improve my problem to make it into like a story about the drag racer

OpenStudy (anonymous):

wording the problem i mean

OpenStudy (anonymous):

Well, you could ask how fast it's going when it reaches the end of a race, assuming a constant acceleration.

OpenStudy (anonymous):

using a positional equation i suppose

OpenStudy (anonymous):

a positional equation?

OpenStudy (anonymous):

well a distance, or position, equation would be the integral of the velocity function, where velocity would be the integral of the acceleration

OpenStudy (anonymous):

The velocity of a drag racer can be described as v(t)=t^2v(t)=t2 where t is in seconds and v is meters per second.. If the object starts at v=0 when t=0, how far has the drag racer traveled after 30 seconds? would this make sense

OpenStudy (anonymous):

Didn't you say you needed to use integrals?

OpenStudy (anonymous):

yeah

OpenStudy (anonymous):

I'm not sure how to do that

OpenStudy (anonymous):

ok, so you could tell them the rate of acceleration the car uses during its race, and explain how to find it's velocity at a given time with that information.

OpenStudy (anonymous):

which would just be the integral of the acceleration.

OpenStudy (anonymous):

okay thank you so much. how could i word that in the problem so it makes sense. sorry for asking so many questions

OpenStudy (anonymous):

ok, um. something like: This car accelerates at 3m/s^2. if it starts a race at rest, how fast is it going 6 seconds later as it crosses the finish-line? The answer would be V(t)= the integral of 3t, which is equal to 1.5t^2+c, and C=0 because it starts at rest. so at time t=6 the answer is 54 m/s...

OpenStudy (anonymous):

awesome thanks so much. i appreciate it

OpenStudy (anonymous):

It is not a realistic equation, nor complex, but something similar should do.

OpenStudy (anonymous):

No prob

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