Question

e^2x (lnx) - e^2x = 0 Solve.

Answer 1

Is it
\[e ^{2x}(lnx)-e^{2x}=0\]
OR
\[e ^{2}x(lnx)-e^{2}x=0\]

Answer 2

e^(2x)(lnx)-e^(2x)=0

lnxe^(2x)-e^(2x)=0

lnxe^(2x)=e^(2x)

lnx=1

e^(lnx)=e

x=e

Answer 3

It's the first one where the 2x is the exponent :)

Answer 4

i see :)

Answer 5

Yeah that's the solution

Answer 6

Thank you!