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Mathematics 20 Online
OpenStudy (anonymous):

find the line that passes through the point (2,5,3) and is perpendicular to the plane 2x-3y+4z+7 = 0

OpenStudy (turingtest):

this problem is almost identical to the last, so I'm gonna make you do a lot more on your own this time ;) 1) what is \(\vec n\) of the given plane?

OpenStudy (anonymous):

(2,-3,4) ?

OpenStudy (turingtest):

yes, nice I just realized that this problem is a bit different though, because it asks for the equation of a normal line, not for the plane similar business though; we still needed the normal vector now we need a line that is parallel to that vector I don't suppose that you know that the equation of a line through a point \(P_0\) is given by\[\vec r(t)=\vec r_0+t\vec v\]where \(\vec r_0\) is the position vector of the given point, and \(\vec v\) is a vector parallel to the line, but that is supposed to be know to solve this problem. I will try to help you understand it anyway though...

OpenStudy (turingtest):

here is a link on the ideas I will express in my explanation http://tutorial.math.lamar.edu/Classes/CalcIII/EqnsOfLines.aspx please open it and look at the picture of the red line

OpenStudy (turingtest):

in this case to use our formula we need to not that the parallel vector in the line formula \(\vec v=\vec n\) because we want a line perpendicular to the plane, which implies it must be parallel to \(\vec n\) because of that we can rewrite this as\[\vec r=\vec r_0+t\vec n\]now you already know \(\vec n\), so now tell me what is \(\vec r_0\) (the position vector that points to the given point)

OpenStudy (anonymous):

(2,5,3)?

OpenStudy (turingtest):

yep, so now you can just plug int the stuff we know why don't you give that a try?

OpenStudy (anonymous):

= (2,5,3)+(2,-3,4) ?

OpenStudy (turingtest):

don't forget the t, which we treat with scalar multiplication (scalar multiplication is this:\(c\vec v=t<a,b,c>=<ta,tb,tc>\))\[\vec r(t)=\vec r_0+t\vec n\]\[\vec r(t)=<2,5,3>+t<2,-3,4>\]\[\vec r(t)=<2+2t,5-3t,3+4t>\]

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

getting it slowly

OpenStudy (turingtest):

by looking at the individual components we can also write this as\[x=2+2t\]\[y=5-3t\]\[z=3+4t\]there are a number of ways to write the equation of a line

OpenStudy (anonymous):

thanks.. next question?

OpenStudy (turingtest):

give me a few minuts, I am eating breakfast and my cat just broke something :(

OpenStudy (anonymous):

haha ok no prob, im goin to take a small break, i will post a new thread for numbr 3, plz reply wen u available..

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