Question

6. What is the gravitational potential energy of the tennis ball at the top of each hill?
Hill A: 80 cm
Hill B: 60 CM
Hill C: 40 cm
Convert to meters please

Answer 1

Conversions:
Hill A = 0.80 m
Hill B = 0.60 m
Hill C = 0.40 m

Now you need the mass of the tennis ball since gravitational potential energy (near the Earth's surface is:\[U=mgh\]Since you didn't post the mass to use let's go with 57g or 0.057 kg.

Now just plug in and solve each for U:
\[Ua = 0.057 kg * 9.8 m/s^2 * 0.80m = 0.44688 => ~0.45 J\]\[Ub = 0.057 kg * 9.8 m/s^2 * 0.60m = 0.33516=> ~0.34 J\]\[Uc = 0.057 kg * 9.8 m/s^2 * 0.40m = 0.22344=> ~0.22 J\]