would you set 16t^2-9 equal to 0 to factor as a trinomial?
You will get (4t-3)(4t+3)
do you mind drawing that out for me because I don't really understand how to get it?
I did something wrong
You sure the question says "equal to 0 to factor"
it says factor
You did factor right, perhaps they meant to solve for t by factoring and setting equal to zero?
It just says factor?
Factor the expression
Ok then I did do it right.
ok, then you don't need to set to zero to factor it, i suppose.
does the question have the zero and the trinomial part?
just the trinomial
ok, then needhelpinmath first answer is right. you would only set it to zero if you were trying to solve for the t. This means (4t-3)=0 and (4t+3)=0 and solve for t. But if the question is really only asking for factor, then needhelpinmath's first answer is enough. :)
thanks:]
\[16t^2-9\] Ones of this type follow the format \[(at-b)(at+b)=a^2t-b^2\] Here, the 16 gives \[16=a^2\] so the a=4. Then, the 9 gives \[9=b^2 \] so b=3. hope this helps some :)
it does thank you very much
welcome ! :)
that was probably the process that needhelpinmath used to get to his/her factored solution.
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