Determine whether each pair of equations represents perpendicular lines y – x = 3 y = –x + 7
to check the prduct of the slopes should be -1
y - x = 3 y + x = 7 ======= 2y = 10 y = 5. Now substitute this value in the equation again to get the value for x.
how did you get the y= 5 though you add up the 7 and 3 to get 10 but how the 5 come along
2y = 10 divide 2 from both sides, \[y = \frac{10}{2}\]\[y = 5\]
ok i see
so do i do the same for x
Now as you have the value for y. now insert in any equation to get the corresponding value of x.
Well we are suppose to see if the lines are perpendicular => you need to ask the question are the slopes opposite reciprocals?
oh man! im blind. Thanks @myininaya for saving the day.
=>if they are, we have perpendicular lines =>if they are not, we do not have such lines
Well unless we have horizontal and vertical lines going on together
But for this case we do not worry about that since we do not
Put both of these lines into y=mx+b form The first equation needs to be put in this form The second equation is already in this form
m is the slope
A plot is attached. The lines, y=x+3 in blue and y=-x+7 in red are perpendicular. A plot is not a proof, however, in the case of school book problems a plot is usually correct regarding mutual perpendicularity. Two lines are perpendicular if the coefficient of the x term of one line is equal to the negative of the reciprocal of the x coefficient of the other line. 1=-(1/-1) ?, 1=1 in this case so the lines are perpendicular.
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