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Write the given function in vertex form by completing the square: y=x^2+9x+2
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Ok! So \[x^2+9x+k\] How do you find k so that this is a complete square?
\[x^2+9x+(\frac{9}{2})^2=(x+\frac{9}{2})^2\] This will always work if the coefficient of x^2 is 1 Just divide the number in front of x by 2 then square like I did above
Now back to finding the vertex form!
\[y=x^2+9x+(\frac{9}{2})^2-(\frac{9}{2})^2+2\] Whatever I add in I must also take out
The form we are aiming for by the way is: \[y=a(x-h)^2+k\]
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So You should be able to write that one part (x^2+9x+(9/2))^2) as a complete square which I at the beginning of this thread
And then all you have to do after simplify if you can such as the -(9/2)^2+2 part
thankyou!
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