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how do you work out the integral of 4t^3 times squareroot(1+9t^4)dt
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try a substitution of a trig function
a trig function? l dont follow
As, \[\int\limits4t^3*\sqrt{1+9t^4} dt=1/9(\int\limits36t^3*\sqrt{1+9t^4} dt)=1/9*{(1+9t^4)^{3/2}}/(3/2)\]
then \[2/27*(1+9t^4)^{3/2}+c \]
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Sorry , a little bit messy :(
Got my way or not
@Muhammad Nauman Umair some of your steps are missing because of the usage of equation...
the steps which i skipped are not difficult to understand @callisto
oh thanx guys that was really helpful
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welcome
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