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Mathematics 18 Online
OpenStudy (anonymous):

Prove that the given subset W is a subspace of V , or show why it is not a subspace of V . V=c∞(R) , W is the set of functions f⊆V for which lim f(x) = 0 x→∞

OpenStudy (anonymous):

i am going to make a quick guess at no, reasoning that subspace must include the zero vector, V does not

OpenStudy (anonymous):

wait, why doesn't V include zero?! the zero function has infinitely many derivitives right?!

OpenStudy (anonymous):

oops sorry, i meant W does not include the zero vector

OpenStudy (anonymous):

why doesn't W include the zero function?!

OpenStudy (anonymous):

oh lord, i should learn to read. i thought it said \[\lim_{x\to 0}f(x)=\infty\] not the other way around. yes it includes the zero vector! ignore me

OpenStudy (anonymous):

ahaha ok, you were scaring me for a sec! i thought i was just starting ot understand this stuff! ok, i'll ask you, for the same question then if it is f(4)=1 instead of the function above, what would the answer be?

OpenStudy (anonymous):

answer to first question is yes, since a) zero vector is in W b) a linear combination of elements of Wis also in W c) a scaler multiple of anything in W is in W

OpenStudy (anonymous):

for the second question the answer is certainly no

OpenStudy (anonymous):

the zero vector is not there

OpenStudy (anonymous):

also if f(4)=1 then \[af(4)=a\] not one, so scaler multiples are not there

OpenStudy (anonymous):

ok great! thank you!

OpenStudy (anonymous):

can i ask you one more by any chance?!

OpenStudy (anonymous):

V = M2×2(R), W is the set of matrices whose square is the zero matrix (i.e., those matrices A with A^2 the zero matrix).

OpenStudy (turingtest):

could you please post this on a new thread?

OpenStudy (anonymous):

yep

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