Question

solve for X using x^2+bx=-c

x^2-x+5
so
x^2+8x=-5
but than im stuck

Answer 1

where did you get the 8 from?

Answer 2

woops accidently took that from a different problem im working on

Answer 3

problem is x^2-x+5=0

Answer 4

i think i use the equation x^2+b/a x = -c/a

Answer 5

use the quadratic formula to solve

Answer 6

or do you have to do it the way you have it up there ^^^?

Answer 7

up there

Answer 8

and that is where im getting lost. Let me try quadratic really fast

Answer 9

quadratic works. I think i got it now lol

Answer 10

oh wait no it doesnt because i get 1-20 within the rational...

Answer 11

x^2-x+5=0
x^2-x=-5
x^2=-5+x
x=sqrt(-5+x)

Answer 12

so this problem has no solution than

Answer 13

because i get 1±√1-20/2

Answer 14

and the square cant be negative right

Answer 15

that's the solution. it's just not exact.
and squares shouldn't be negative.

Answer 16

Hmm... ok thanks