Write the slope-intercept equation for the line that passes through (-5, -8) and is perpendicular to 10x – 6y = -11 Please show all of your work
Eep. . ok. perpendicular means \[m2 = \frac{-1}{m1}\] so you start with m1 which is in your original equation, then solve for m2 which is the slope for the equation that is perpendicular.
first, find the slope of this 10x – 6y = -11 change to the format of y=m*x + b so, subtract x from both sides: – 6y = -11 -10x then divide whole equation by -6 y = (-11/-6) -(10/-6)x rearrange it for proper format: y = -(10/-6)x +(-11/-6) simplify the - and +: y = (10/6)x +(11/6) simplify the fraction: y = (5/3)x +(11/6) so, slope m = 5/3 and y intercept b=11/6 ok?
so for your original equation, the slope is m1 = 5/3 to find the perpendicular slope, \[m2 = \frac{-1}{5/3} = \frac{-3}{5}\] use this new slope and that point you were given to fine the new equation... m2=(-3/5)
Point: (-5, -8) slope: m= -3/5 put into equation format: (y-y1) = m * (x-x1) x1 = -5 y1 = -8 m = -3/5 (y-(-8)) = (-3/5) * (x-(-5)) minus a negative is + y+8 = (-3/5) * (x+5) multiply through by the -3/5 y+8 = (-3/5) * x + (-3/5) *5 simplify: y+8 = (-3/5) * x -3 subtract both sides 8: y = (-3/5) * x -11 therefore, slope intercept form is y = (-3/5) * x -11 slope is -3/5 y intercept is -11
ok?
got you
Good luck !
thanks soooooo much
you're welcome ! hope you get a good score and understood well enough!
me too lol
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