Write the equation of the line that is perpendicular to the line y = x + 4 and passes through the point (−6, 3).

y = 3/2x − 1

y = 3/2x + 3

y = −2/3x − 1

y = −2/3x + 3

Question

Write the equation of the line that is perpendicular to the line y = x + 4 and passes through the point (−6, 3).

 y = 3/2x − 1

 y = 3/2x + 3

 y = −2/3x − 1

 y = −2/3x + 3

anonymous · Answer

what do you know about slope of perpendicular line?

anonymous · Answer

perpendicular slope will be -1

anonymous · Answer

using the perpendicular slope and  point (-6,3) the line will be. . .

anonymous · Answer

the answer is not found on the choices. .

anonymous · Answer

using point-slope form, given the perpenducular lope and the given point, the equation of the line will be y= -x -3

mysesshou · Answer

point (−6, 3).
 y = x + 4 
m=-1
y+6 = -1*(x-3)
y= -x+3-6
y=-x-3

agree with  jerwyn gayo

also easily seen as original slope is 1, so perpendicular slope is -1, and none of the answers have -1 as the slope.