If dy/dx is 2x-7 in an initial value problem, and y(2) = 0, how do I go about solving this? I tried plugging in 0 for x, but I don't think it's quite that simple...

Question

anonymous · Answer

u need to integrate 2x-7. do u know how to do that?

anonymous · Answer

is that finding the antiderivative?

anonymous · Answer

yes :d

anonymous · Answer

ok,so it's x^2 - 7x. Um, Idk what to do after. Plug 2 in?

radar · Answer

What are you solving for?

anonymous · Answer

It just says "solve the initial value problem" and the answer is an equation, but I have no idea how it got there. Answer is: x^2 -7x +10. So I guess I'm looking for C using y(2)=0?

anonymous · Answer

from x^2 - 7x +C from integrating original prob.

radar · Answer

So you are to solve for C Hmmm.    0=2^2 -14 + C    substituting 2 for x
0=4-14+c
C=10
Would that work?

anonymous · Answer

Oh wow, that works! Thanks! :)

radar · Answer

I hope that is the correct procedure, and you are certainly welcome.  good luck with your studies.