Graph the relation in the table. Then use the vertical-line test. Is the relation a function?
x:-1 , 1 , 2 , 1
y:3 , 0 , -1 , 2 , 3

Question

Graph the relation in the table. Then use the vertical-line test. Is the relation a function?
x:-1 , 1 , 2 , 1
y:3 , 0 , -1 , 2 , 3

anonymous · Answer

Given 4 x-coordinates, and 5 y-coordinates? Hmm...

anonymous · Answer

Seems okay to me.

anonymous · Answer

We don't know what part of $\{x\}$'s domain is mapped to which part of $\{y\}$'s.

anonymous · Answer

What's wrong in treating as Injection?

anonymous · Answer

this*

anonymous · Answer

Ahh , these graphs annoy me ! lol

anonymous · Answer

I am assuming: (-1,3),(1,0) ...

anonymous · Answer

So this is a one-one function or injection.

anonymous · Answer

Not sure how to treat this as an injection unless we're given more elements in $y$ than in $x$.

anonymous · Answer

Woops, I mean equal.

anonymous · Answer

Oh wait, not a bijection, ignore me. lol

anonymous · Answer

Injection doesn't requires to be equal elements.

anonymous · Answer

Sp do i just graph them ? or ..

anonymous · Answer

and yes  bijection and surjection does . lol it's okay :)

anonymous · Answer

So*

anonymous · Answer

Presumably you graph the first four points if each number of the domain's element corresponds to the codomain's? But then that requires we assume that's the case.

anonymous · Answer

Actually i'll skip this one .