Question

f(x)=-(x+3)(x-5) finding min and max x/y intercept

Answer 1

you're in calc too? lol

Answer 2

right
i need help

Answer 3

i suck at calc lols
i think u set both -x-3 and x-5 to zero and solve

Answer 4

with calc you can find min/max using criticle point

Answer 5

how do i do that

Answer 6

to find criticel point , take derivative and set what you get to zero

Answer 7

can u write it out..

Answer 8

please

Answer 9

he means critical points

Answer 10

y=-(x+3)(x-5)

let's use product rule to differentiate

- (x+3)'(x-5)+(x-3)(x+5)'= - 1(x-5)+(x-3)

Answer 11

k

Answer 12

http://openstudy.com/study#/updates/4f6a89fde4b014cf77c7bc83

Answer 13

king explains it well here

Answer 14

idont udnerstand kings way. haha

Answer 15

can u actaully help me with all of number u on this attatched file

Answer 16

i understood it :(

Answer 17

can u guys help me with wat i attached above i need help on number 6a-f

Answer 18

what do you think is domain for 6) a)

in other word is there any number that you can't put in for x?

Answer 19

anything above 6
?

Answer 20

why not anything below 6 into

f(x)=5+3x

Answer 21

i dont know

Answer 22

could it be anything

Answer 23

YES

Answer 24

why

Answer 25

you can put anything number and you won't get in problem so your domain is all real number

Answer 26

wwhat about range

Answer 27

domain is number you put in for x , range is number you get back as y as result of you putting value for x

Answer 28

if you can put all value for x, you will get any value of y

so range is also all real number

Answer 29

ok
now b

Answer 30

b is same thing

Answer 31

so is c

Answer 32

d) is different

tell me what number can't we put in?

Answer 33

error

Answer 34

shows up

Answer 35

?

Answer 36

what do you mean?

Answer 37

in the calculator ..

Answer 38

for what number did you get an error?

Answer 39

-1 -2 -3 -4
and all negative

Answer 40

ok , so we can't put negative number in there , 0 is fine

so domain is

x must be greater or equal to 0

x>=0

Answer 41

how bout range

Answer 42

square root only return positive values

sqrt[0]=0
sqrt[1]=1
sqrt[4]=2
ect.......

so range is too
y>=0

Answer 43

ok

Answer 44

alright, I forgot to do range for b and c

Answer 45

yeah

Answer 46

y= x^2

y of that function goes from 0 to infinity

if we shift that up

y=x^2+4

y goes from 4 to infinity

Answer 47

ok

Answer 48

for c) well just look the graph
http://www.wolframalpha.com/input/?i=(1.5)%5Ex&t=crmtb01

goes from 0 to infinity

Answer 49

ok

Answer 50

alright.

Answer 51

i need e nd f

Answer 52

what do you think?

Answer 53

any number for domain

Answer 54

yes

Answer 55

range?

Answer 56

y=-x^2

goes from -negative infinity to 0

so

y=-x^2+2
is shifted up by two

Answer 57

how about f

Answer 58

?

Answer 59

what numbers doesn't works?

Answer 60

any number below o

Answer 61

wait can u help me to explain number 5 i got the answers but idk how to explain the meaning

Answer 62

no, only number that doesn't work is 0

Answer 63

how about range

Answer 64

all real number

Answer 65

i need help explainging what 5 means
a-d

Answer 66

make another thread